Fan 8082D Bidirec...

  • 2022-09-23 10:29:47

Fan 8082D Bidirectional DC Motor Driver

feature

Built-in braking function, stable braking performance.

built-in components that absorb from

Change the motor direction and brake the motor drive.

Motor speed is controlled by external voltage.

Motor direction changes are stable.

interface with CMOS devices.

Built-in thermal shutdown circuit ( 165 °C).

Low standby current. (6.5mA)

illustrate

FAN8082D is a monolithic integrated circuit

Bidirectional DC motor control for driving with brake and speed, suitable for VCR, CDP and toy systems. Speed control can be achieved by an external voltage regulating the speed of the control pin. It has two logic input pins for controlling forward/backward and braking

typical application

Low current DC motors for CD player trays or changers, such as audio or video equipment. Universal DC Motor

absolute maximum ratio


notes:

1. Duty cycle 1/100, pulse width 500 microseconds

2.1) When mounted on epoxy glass substrate (76.2×114×1.57mm)

2. When using higher than Ta=25°C, the power consumption is reduced by 2.64mW/°C.

3. Do not exceed Pd and SOA (Safe Operating Area).

Power consumption curve

Recommended operating conditions (Ta=25°C)

Note:

Warning 1) PVCC≤SVCC

Note 2) VCTL must be open or 4.0≤VCTL≤PVCC

Electrical Characteristics (SVCC=PVCC=12V, Ta=25°C)

application information

1. Thermal shutdown circuit

When Ta=25°C, Q2 and Q3 are turned off and the output stage works normally.

V1=I×(R1+R2)

V2=R2/(R1+R2)×V1=0.37V

When Ta=165°C, Q2 & Q3 are turned on and the output stage is turned off.

0.70V-0.37V=330mV (when Q2 and Q3 are turned on, VbeQ2=VbeQ3=0.70V)

Temperature coefficient Q2=Q3=-2mV/℃∴TSD:330mV/2mV=165℃

2. Logic input and output table

The input voltage is higher than 2.0V.

Input low voltage below 0.7V.

Low: All power TRs are off.

But the internal bias keeps the output voltage in a low state

3. Logic switch circuit

This circuit defines the reference voltage for the output. When pin 4 is "H" and pin 5 is "L",

-V1=Vzd+VbeQ4+VbeQ5·=·8.9V

-V2=Vbeq 7+VsatQ6...0.87V

V1 and V2 are related to the output voltage of the motor and vary with the voltage at pin 3 (VCTL).

4. Drive output circuit

V1=8.9V

V2=0.87V

VO1=V1-VBEQ1-VBEQ2

VO2=VQ6SAT

VO=VO1-VO2=V1-VBEQ1-VBEQ2-VQ6SAT

IRL=(VO1-VO2)/RL

Typical performance characteristics

test circuit

application circuit